CHEM 1212 Quiz: CHEM1212 Kennesaw State Quiz 4 Solutions
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Sample quiz 4 answers: w = -p v = -(6. 00 atm)(1. 00 l - 6. 00 l) = +30. 0 l atm x. E = q + w = 0 + 3. 04 kj = 3. 04 kj. = 3,039 j = +3. 04 kj: s = (213. 63) + (130. 57) - (197. 56) - (188. 72) = -42. 08 j/k. S = 269. 2 j/k - 172. 8 j/k = 96. 4 j/k. G = h - ts if g = 0 then t = = 352 k: g = -rt ln k ln k = Al is being oxidized, it is the reducing agent. Sn is being reduced, it is the oxidizing agent. E red = +0. 80 v (aq) + 2ag(s) e cell = +0. 46 v: e = e - Mg (reduction half reaction) (oxidation half reaction) Cl2 + 2e q = i x t = (2. 50 a)(5400 s) = 13,500 coulombs x.
