CHE 3101 Final: Ch 13
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0. = o dv dy dv dy dv. , for n = 1 this becomes = k which is the same as eq. = 0; yield , = yield + o for yield this becomes dy which is also the same as eq. , a = dy as , a as 0, a + b a. ) = b; b = 0 dy (b) = + 2 (dv / dy) 0, 0 as (dv / dy) , p ; as. A as dv / dy , , c+1 1. 0 = 1 / a , ( dv / dy) lim dv (1/ ( c+1)) dv. 13. 4* as best i can read fig 13. 2, at 200/s the values on the curves, from the bottom are (lbf/ft2) : 0. 63, 1. 76, 2. 0, 2. 2, 2. 5, and 2. 6. The best fit straight line shown has the equation. Solutions, fluid mechanics for chemical engineers, third edition, chapter 13, page 1.
