CHEM 1202 : Test 2 Solutions
Document Summary
The sign of g can help us identify the direction of spontaneity for a reaction at constant temperature and pressure. (we must assume that is true. ) We know the signs are exothermic means h 0 and increasing order means s 0 so we can write the equation for g using only the signs. For the initial condition where the process is reversible g 0. Now suppose temperature is decreased and the reaction takes place at a lower temperature. When t decreases t becomes a smaller positive number and g becomes negative. The reaction becomes spontaneous at the lower temperature because. When the process is reversible, the two terms in the equation cancel and give g 0. When t decreases the t term makes g 0 and the process becomes spontaneous. Kp kc rt n: 105 5 10 5 kc . 0 using the second order rate law equation. A : 693 1 10 2 t .
