PSIO 532 Study Guide - Final Guide: Nephron, Renal Vein, Inulin
Document Summary
What if [pah] is higher than able to be completely secreted in one pass thru the kidney? filtrate has 200,000 mg pah in 100 ml: 350 ml/min plasma (containing 700,000 mg pah) perfuse the tubules. If tubular transport maximizes at 500 mg/min (we are using an example) tubules secrete maximum possible pah or 500 mg/min. Tubules will also overall reabsorb 99 ml_ filtered water: v = 1 ml/min, upah =200,000+500 = 200,500 mg/ml, rvpah = 799,500 mg/499 ml renal venous plasma flow = total rpf - v = 499 ml/min. In this example, the concentration of pah in the plasma is very high. Note that when the concentration of pah exceeds the ability of the tubule to secrete the. Pah that was not filtered, then the clearance of. Pah will not equal the effective rpf but will approach the value of gfr. If apah is high, then cpah approaches gfr. Given: upah = 200,500 mg/ml, het = 40%
