MATH 1172 Midterm: MATH 1172 2012-AU-Midterm-2-ANS-om1dbt

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31 Jan 2019
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MATH 1172 Full Course Notes
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Form a, page 2: h20 ptsl evaluate the integral or state that it diverges. Hx - 1l hx + 1l ix2 + 1m = = ia hx + 1l ix2 + 1m + b hx - 1l ix2 + 1m + hcx + dl ix2 - 1mm . Ihx - 1l hx + 1l ix2 + 1mm x = 0 h1l 1 = a - b - d; x = 1 1 = 4 a a = 4 x = -1 1 = -4 b b = - 4 in h1l, we get that 1 = x = 2 1 = = lim b ln hx - 1l - 4 ln x - 1 x + 1. Form a, page 3: h22l hil determine the interval of convergence of the series . k=2 k xk k ! Hil h10 ptsl determine the interval of convergence, Solution : r = lim k ak+1 ak lim k .

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