MATH 1172 Midterm: MATH 1172 Ohio State University Math 1172 13.1 Solutions Fa 2014

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31 Jan 2019
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MATH 1172 Full Course Notes
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November 19, 2015: find an equation for the plane passing through the point (1, 2, 3) and normal to the vector h1, 1, 1i. Solution: as given by the above equation, the equation for the plane we are interested in is. 1(x 1) + 1(y 2) + ( 1)(z 3) = 0. After simplifying x + y + z = 0: find an equation for the plane de ned by the three points (1, 1, 1), (0, 4, 0), and ( 2, 3, 1). Solution: first let us use the cross product to nd a vector normal to the plane. 3 2 (cid:12) (cid:12) (cid:12) (cid:12) (cid:12) (cid:12) = i(3 0 ( 1) 2) 2x + 3y + 7z = 12: find an equation of the plane parallel to the plane q : x 2y 3z = 4 going through the pt (2, 0, 4).

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