MAT 132 Midterm: MAT 132 SBU Exam Midterm 126s10 Solution

24 views6 pages
31 Jan 2019
Department
Course
Professor
MAT 132 Full Course Notes
2
MAT 132 Full Course Notes
Verified Note
2 documents

Document Summary

Solutions to midterm 2 (electric: determine these easy antiderivatives. Z 2 x dx = 2 ln|x| + c. Z 2 sin(x) dx = 2 cos(x) + c. Z dt = 2 arctan(t) + c du. 1 u2 du = arcsin(u) + c: in this question we tell you which method we suggest you use. Solution: make the substitution u = 1 + y2, so that du = 2dy, or 1. Note that since 1 + y2 > 0 for all y, the absolute value is not necessary; the answer ln(1 + y2) Solution: make the substitution u = x + 1. X + 1 dx = 2z eu du = 2eu + c = 2e x+1 + c. Solution: here, we let u = ln(z) and so du = dz z. Z ln(z) z dz =z u du = Thursday march 25, 2010: in this question we tell you which method we suggest you use.

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers

Related Documents

Related Questions