MATH 151 Midterm: MATH 151 TAMU Y2014 2014c X1B Solutions
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Fri, 03/oct c(cid:13)2014 art belmonte: (c) we have. 4t 2 + t + 1 lim t . Here are various vector notations: v = v1i + v2j = hv1, v2i = [v1, v2]. The magnitude of v is denoted by |v| or kvk: (a) via scalar multiplication and vector addition, 2a 3b = 2 [2, 3] 3 [3, 1] = [ 5, 9] = 5i + 9j: (b) a vector joining points (1, 3) and (4, 1) is given by v = [1, 3] [4, 1] = [ 3, 4]. A unit vector parallel to v is v = v/kvk = [ 3, 4] / 9 + 16 =(cid:2) 3: (e) the scalar projection of b = [2, 1] onto a = [1, 1] 2 a b kak: (d) a direction vector for the line y = 2x + 3 is v = [1, 2]. 4 (y 1)2, the graph of which is a whence x = 1 parabola.
