MAC 2312 Midterm: Test 2 study guide

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QUIZ 7.3 &7. 4
.
Test 7. 3
,
7.4 ,
7.8
8. I
1
restrictions cnio ?
Expression Substitution Identity .
May × = a sin 01-Sino =cos2o ¥±o±zI
Ttf ×= a + an gIt + an2G = seczo -Iz L
GL
Iz
-× = a Seco geczg .,=+anzq 0£04 °r
×
2
-a2 itc GL
Example 1
g¥-2 dx
×2
1use of -7 X = a Sino -7I-Sih2 0 = ( 0520
*
tacos -0
¥2 =jffsinto =Togo = 3 cost
fF÷I=f3c°sI3coso=f
450,3¥ =fcot2o=Scsc2o
-i
4Sin2 G4
(l+cot2=CSc2 -0 )
f¢sc2o -1) do =-cot -G + C
(
fcsdu =-cot + c )
2Triangle graph -7 return to X
X =35in G-7 Sino =I-7 e =sin
'§
3
3
X-cot -G + (=
1)
ofLv
32-xT -F#
-Siri 'S
×
-9¥
a-
-sin
'' ×z + C
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.
Example 2Find area enclosed by the ellipse
*+¥2 =1
102
y=¥Mae 0< ×£a* only Iof area
±A=fao Ifafxz ax
a
1use FE -7 × = a sin G -7Sin 2G-1= COSZG
dx = a Cose
<
ftp.b#a2siFoCacoso7=4f*
"±(acoso )@
cost )
aa
0
=450
a2cos2o =
tabfto"coszo =4ab[o
"
tz (ltcoszo )
a
=Zab [0
+
tzsinzo ]MY =Zab (Iz to -o)= Tab
Example 3f1- Example
4×2-2+4
Sub tan but easier to Sub U
1 use Mae -7 ×=atano ->+ anzo + 1= seczo f. ×¥f dx
* Could
dx=asec2 -0 (-Iz <0 L Iz )
2Ft .> × =
ztano -7 fleets =M¥0 =2sec0= a = ×2+y du = ×= ¥
3fnatnzsec ,25×20=5 III. = IS tzfudu
= tzffu du ='z( 2k ) + c = Su + C =FEu + c
"Ishii .IS#sn . #
Example 5
g Substitute U = Sin × du = cos X
'
IS Isdn =-÷,(1) + c =-I + c = =
,
'zn + c f×£#z a> °
6
,
+ano=±#
1 use Fta ' '
axI.az#oIansoea2-'=tan2
X2T.az -7FEAT = afar = at an -0
v
.-
-
tote .
" =
-F¥+c
a
z
3fading asec + an =Sasec = in Isecuttanul + C
4
Example 6
ftp.#3a...'@xFasYsIaIaCyxT)3
5
lnlsec + tanl + C = in |Ia + FEI |+ C = In 1×+5×-2.1 + c
* combine a sub with tangent Sub
1
Example 7
53¥72
= 3-2×-1-2 =3-(2×+1,2) = 3+1 -(2×+1-2+1)
= 4 -(x + IT
a = 2 sin Q
S¥r¥yY
,
' 'SEE
du=zc°s*
I if =
Cs ,n2 .
-LE = 2 cos
2 SEE
''Ic°T×
.
= S zsinx .1 =-ecos G + C
¥4
IIIe it÷al
.sin
=-FI -sin
' '
uz + C
=-F- xr -sin
'' ( ¥)+ c
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