MATH 31A Midterm: Math 31A Exam 4

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7 Mar 2019
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This test is closed book and closed notes. For full credit show all of your work (legibly!). First we note that to nd the tangent line to g(x) at x = 3 we need to compute g(3) and g (3). Using the rules of derivatives we have g (x) = 6xf (x) + 3x2f (x). So we have the following. g(3) = 3 32f (3) 6 = 27f (3) 6 g (3) = 6 3f (3) + 3 32f (3) = 18f (3) + 27f (3) So what we really need are f (3) and f (3). So we have the following. g(3) = 27( 1) 6 = 33 g (3) = 18( 1) + 27( 2) = 72. Finally, the tangent line will be y = g(3) + g (3)(x 3) = 33 + ( 72)(x 3) = 72x + 183: let (x) be the function shown below.

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