PHYS 211 Quiz: Rotational Dynamics

47 views6 pages

Document Summary

= (2/5)*kinetic energy = less than kinetic energy. There is both a non-zero net torque and force on the cylinder. The cylinder will undergo angular acceleration but not linear because the cylinder is fixed in a spot. Inertia for a cylinder is the same as disk, (1/2)*mr2 (1/2)*. 05*. 05*4 = 0. 005. Torque is equal to angular acceleration * inertia. I think i can divide the force by the mass of the solid cylinder to get linear acceleration. Well it starts from rest, so angular acceleration*time = angular velocity. No translational because it"s not moving, just spinning. Blue solid disk mass = 2. 4kg radius = . 1m. Orange sphere mass = 4. 3kg radius = . 17m. Well let"s act like it"s a regular pulley system that we have been doing. Weight of the green hoop is 2. 7*9. 8 = 26. 46n. 26. 46n is the force on the entire system. Nevermind we can"t ignore the rotational dynamic torque = i*angular acceleration.

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers

Related textbook solutions

Related Documents