STAT 571 Midterm: STAT 571 UW Madison f98Mid2 Solutions

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31 Jan 2019
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Stat/for/hort 571 midterm ii, fall 98 . Brief solutions: let p1 and p2 be the rates of mutation for the rst and second procedures, respectively. H0 : p1 = p2 vs. ha : p1 6= p2. P1 p2 z = p p(1 p)(1/n1 + 1/n2) where p is the pooled estimate of p = p1 = p2 (under the null) given by (9 + 16)/(358 + 339) And n1 p1 = 9, n1(1 p1) = 349, n2 p2 = 16, n2(1 . P2) = 323 so that the normal approximation is justi ed. We have dftrt = k 1 = 4 and dftot. = n 1 = 29 so that dferr = 25. Noting that ms = ss/df, we obtain the anova table: Let v 2 be the chi-squared dis- tribution with 25 df and note that p (v 2 13. 12) =