EBIO 1210 Chapter Notes - Chapter 13: Genetic Engineering, Heterochromatin, Euchromatin

30 views2 pages

tealhedgehog29

6 Mar 2016

School

CU-Boulder

Department

Ecology & Evolutionary Biology

Course

EBIO 1210

Professor

Randolf Didomenico

For unlimited access to Textbook Notes, a Class+ subscription is required.

Document Summary

Transformation- a change in genotype and phenotype due to the assimilation of external dna by a cell. Chargaff"s rules: base composition varies among species, within a species, the number of a equals t, c equals g. Structure of dna: run antiparallel, a and g are purines which have 2 rings, c and t are pyrimidines which have 1 ring. The semi-conservative model- 2 parental stands spate and each function as a template for synthesis of a new, complementary strand: new daughter molecule will have one old strand and one new strand. This strand is synthesized discontinuously into segments called okazaki fragments and each fragment must be primed separately. Dna pol 3 forms the fragments, then dna pol 1 replaces the rna nucleotides of the adjacent primers with dna nucleotides and then they are joined by dna ligase. A chromosome consists of dna packed with proteins: bacteria have one double stranded circular dna with a small amount of protein.

Related Questions

In addition to identifying the genetic material, the experiments of Avery, MacLeod, and McCarty with different strains of Streptococcus pneumoniae demonstrated that

	DNA is a double helix.
	DNA may be taken up by bacterial cells and be active.
	DNA is present in bacteriophage T2.
	eukaryotic cells may be genetically transformed.
	DNA binds to the cell wall of the bacterium.

In order to show that DNA in cell extracts is responsible for genetic transformation in Streptococcus pneumoniae, important corroborating evidence should indicate that _______ also destroy transforming activity.

	temperatures high enough to kill cells
	enzymes that hydrolyze proteins
	enzymes that hydrolyze DNA
	enzymes that hydrolyze polysaccharides
	enzymes that hydrolyze RNA

Based on what you have learned about the experiments conducted by Griffith and Avery and colleagues with bacteria, which of the following would result in transformation of living R cells?

	Pure RNA from S cells
	Cell-membrane extracts from S cells
	A mixture of pure RNA and protein from S cells
	Cell-free extracts from S cells
	Pure protein from S cells

A-T base pairs in a DNA double helix

	form three hydrogen bonds with each other.
	are more heat-stable than G-C base pairs.
	are of a substantially different length than G-C base pairs.
	are not accessible to DNA binding proteins.
	are chemically distinct from G-C base pairs.

If 23 percent of the bases in a sample of double-stranded DNA are adenine, what percentage of the bases are uracil?

	27
	50
	0
	73
	23

The uniform diameter of the DNA structure provides evidence for

	antiparallel DNA strands.
	a right-handed helix.
	a double-stranded helix.
	3â² end phosphorylation.
	purineâpyrimidine pairing.

If a sequence of one strand of DNA is 5â²-TGACTATC-3â², what is the complementary strand?

	5â²-ACTGATAG-3â²
	3â²-TGACTATC-5â²
	3â²-ACTGATAG-5â²
	3â²-ACTGATAG-3â²
	5â²-TGACTATC-3â²

What structural aspect of the DNA facilitates dissociation of the two DNA strands for replication?

	3â² end phosphorylation
	Purineâpyrimidine pairing
	Antiparallel DNA strands
	Covalent bonds between sugars and phosphate groups
	Hydrogen bonding between paired bases

If the MeselsonâStahl density gradient experiment had resulted in two bands of DNA molecules after only one round of replication, one containing only ¹⁵N and the second only ¹⁴N, this result would have indicated that replication was

	unidirectional.
	dispersive.
	conservative.
	bidirectional.
	semiconservative.

10.

The nucleoside analogue acyclovir, which is used to treat herpes simplex virus (HSV) infections, lacks a 3â² hydroxyl group (âOH). Predict what will happen if the host cell DNA polymerase incorporates a molecule of acyclovir into an elongating strand of HSV DNA.

	The replication complex will no longer bind to origins of replication.
	The DNA polymerase will only incorporate acyclovir molecules.
	Acyclovir will bind single-strand binding proteins.
	DNA polymerase will not be able to link a successive nucleotide.
	Acyclovir will block the activity of the DNA helicase.

11.

Which of the following does not demonstrate the stability of the DNA double helix?

	Single-strand binding proteins are required to keep the strands apart.
	Paired bases form hydrogen bonds.
	High temperatures are required to denature it.
	DNA synthesis requires energy.
	DNA helicases require ATP.

12.

What effect would a primase inhibitor have on DNA replication?

	DNA polymerase would not be able to add bases to the DNA.
	Primase would be blocked from joining the DNA replication complex.
	Primase would not be able to provide primers for DNA polymerases.
	DNA polymerase would not be able to use DNA as a template.
	There would be no effect on DNA replication.

13.

To replicate their DNA in a timely manner, most eukaryotic chromosomes

	normally have uncoiled DNA.
	have multiple origins of replication.
	contain linear molecules of single-stranded DNA.
	have two replication forks that move in the same direction.
	are composed entirely of DNA.

14.

Which statement about DNA replication is false?

	Okazaki fragments are synthesized as parts of the leading strand.
	Error rates for DNA replication are reduced by proofreading of the DNA polymerase.
	The sliding clamp increases the rate of DNA synthesis.
	Replication forks represent areas of active DNA synthesis on the chromosomes.
	Ligases and polymerases function in the vicinity of replication forks.

15.

In many eukaryotes, there are repetitive sequences called telomeres at the ends of chromosomes. After successive rounds of DNA replication, the _______ strand becomes shorter. In some cells, an enzyme called _______ repairs the shortened strand.

	leading; telomerase
	lagging; telomerase
	lagging; DNA polymerase I
	leading; DNA polymerase I
	leading; replicase

16.

A researcher studies normal human fibroblast cells. They can be maintained in culture but die off after about 30 cell generations. Unexpectedly, a colony of cells continues to survive and divide past 30 generations. Which scenario is most likely true for these cells?

	DNA polymerase is constantly active.
	Primase is able to extend the telomeres.
	The mismatch repair system is extra efficient.
	The telomerase gene is being expressed.
	The cells do not need the ends of their chromosomes.

17.

If DNA polymerase III introduces an incorrect nucleotide, what is the first corrective action made by the DNA repair system?

	The replication complex excises the incorrect nucleotide.
	The excision repair proteins remove the incorrect nucleotide.
	The mismatch repair system scans for base-pairing mismatches.
	There is no correction, because nucleotide errors by DNA polymerases are not repaired.
	DNA ligase connects the correct nucleotide.

18.

Choose the correct order of the following four events in the excision repair of DNA:
(1) Base-paired DNA is made complementary to the template.
(2) Damaged bases are recognized.
(3) DNA ligase seals the new strand to existing DNA.
(4) Part of a single strand is excised.

	1, 2, 3, 4
	2, 1, 3, 4
	3, 4, 2, 1
	2, 4, 1, 3
	4, 2, 3, 1

19.

Six complete cycles of PCR should result in a _______-fold increase in the amount of DNA.

	64
	32
	12
	128
	6

20.

When double-stranded DNA is heated to temperatures above 90Â°C, it denatures. Denaturation is a process that

	breaks covalent bonds.
	hydrolyzes DNA.
	separates double-stranded DNA into two single strands.
	causes new hydrogen bonds to form.
	irreversibly destroys the double helical structure.

Match each term with its definition. Each term or definition is used only once

- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	right-spiraling common DNA form
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	referencing the opposite orientation of hydrogen-bonded DNA strands
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	viral particle whose natural host is a prokaryote
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	universal holding that the number of purines always equals the number of pyrimidines
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	nucleic acid base sequences able to form a double-stranded structure by virtue of matching base pairs
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	5ââ 3â or 3ââ 5â
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	nuclease able to cleave phosphodiester linkages in the DNA backbone
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	the structure formed by two DNA strands twisted around a common axis in a spiral
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	bacterial cycle of phage- infected cells resulting in cell destruction and viral release
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	main access site for proteins that recognize specific DNA sequences
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	a cytosine modification favoring Z DNA formation
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	nucleic acid monomer consisting of a sugar, a phosphate group, and a nitrogenous base
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	connects two nucleic acid sugar molecules via an ester bond
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	hydrolyzes peptide bonds linking amino acids
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	U or C in RNA
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	a pentose sugar
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	an enzyme that breaks down RNA
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	either of the two nucleotide chains of a double helix
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	a pyrimidine able to hydrogen bond with adenine
- A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T.	a DNA configuration favored by high ionic strength and GC repeats

A.	protease
B.	lysis
C.	double helix
D.	bacteriophage
E.	complementary
F.	Chargaffâs rule
G.	B DNA
H.	major groove
I.	nucelotide
J.	antiparallel
K.	RNAse
L.	directionality
M.	phosphodiester linkage
N.	ribose
O.	Z DNA
P.	pyrimidine
Q.	methylation
R.	DNAse
S.	uracil
T.	strand

magentaraven576

Which of the following did Erwin Chargaff observe?

A)	Base composition changes as the organism ages.

B)	Base composition of DNA does not vary from one species toanother.

C)	In all species the number of adenines equals the number ofguanines.

D)	In all species A + T = G + C.

E)	DNAs isolated from different tissues of the same species havethe same base composition.

The melting temperature (Tm) of a DNA duplex is:

A)	the temperature at which double-stranded nucleic acids degradeinto free nucleotides.

B)	the temperature at which double-stranded DNA is toosingle-stranded to ever renature back to double strands.

C)	the temperature at which double-stranded DNA is completelymelted.

D)	the temperature at which double-stranded DNA has become 50%single-stranded.

E)	the temperature at which double-stranded DNA begins to melt.

Given your knowledge and the descriptions of each of thesemethods, which of the following does NOT rely on the ability ofnucleic acids to hybridize with each other?

A)	Southern blotting for the detection of specific DNA fragmentsthat have been separated by gel electrophoresis.

B)	Colony blot hybridization to identify a specific sequence from acollection of sequences that have been inserted into bacteria.

C)	Northern blotting for the detection of specific RNA fragmentsthat have been separated by gel electrophoresis.

D)	A DNA oligonucleotide microarray incubated with probes made fromcDNA.

E)	Western blotting for the detection of specific proteins thathave been separated by gel electrophoresis.

Which of the following is a possible reason why DNA uses thymineinstead of uracil?

A)	Cytidine is deaminated to uracil so it would be difficult forany repair mechanism to differentiate between uracil that belongsin the sequence and uracil that resulted from deamination.

B)	Adenine is deaminated to uracil so it would be difficult for anyrepair mechanism to differentiate between uracil that belongs inthe sequence and uracil that resulted from deamination.

C)	When uracil is bound to a deoxyribose it will become morereactive, forming covalent bonds with other bases.

D)	None of the above.

Which of the following is an enzyme used in cloning to breakcovalent bonds?

A)	DNA ligase

B)	Restriction endonuclease

C)	Reverse transcriptase

D)	DNA polymerase I

E)	Alkaline phosphatase

Which of the following could you use to remove the 5' phosphatesafter cleavage of a plasmid with a single type of restrictionenzyme to ensure that the plasmid would not simply fuse backtogether upon addition of ligase?

A)	Reverse transcriptase

B)	Alkaline phosphatase

C)	DNA ligase

D)	DNA polymerase I

E)	Restriction endonuclease

Which of the following would you use to create a cDNA librarythat you would not use for a genomic library?

A)	Alkaline phosphatase

B)	Reverse transcriptase

C)	Restriction endonuclease

D)	DNA ligase

E)	DNA polymerase I

A plasmid vector typically has which of the followingfeatures?

A)	An origin of replication

B)	A selectable marker to ensure that the only bacteria growingcontain the intact or recombinant vector.

C)	Unique restriction sites for insertion of DNA.

D)	Small size to facilitate entry into the cell and biochemicalmanipulation of the DNA.

E)	All of the above are features of plasmid vectors.

Which of the following is FALSE of genomic or cDNAlibraries?

A)	Genes represented in cDNA libraries include control sequencesthat direct transcription.

B)	cDNA libraries contain cDNAs made from mRNA.

C)	Genomic libraries contain fragments of genomic DNA that aregenerated by partial digests with restriction enzymes.

D)	Genomic libraries usually contain large fragments and are likelyto be constructed in YAC or BAC vectors.

E)	cDNA libraries contain sequences from expressed genes only.

Which of the following is NOT a typical component of apolymerase chain reaction (PCR)?

dNTPs

B)	DNA containing the sequences to be amplified

C)	DNA ligase to connect the fragments together

D)	Primers complementary to each end of the sequence to beamplified

E)	Heat stable Taq polymerase

How can a fusion protein be formed?

A)	Site-directed mutagenesis where a fragment is replaced with asynthetic sequence containing the altered DNA sequence.

B)	Two proteins can recombine in the bacterial cell to form a newhybrid protein.

C)	Portions of two different genes are ligated together to create anew hybrid gene. When expressed the gene product is a fusion of thetwo gene products.

D)	Using oligonucleotide-directed mutagenesis to introduce specificmutations that cause the expressed protein to fuse to otherproteins.

E)	A portion of the gene can be removed to form a shorter gene andtherefore a shorter protein.

Why is green fluorescent protein (GFP) so useful in visualizingfusion proteins in eukaryotes?

A)	The GFP protein recognizes and binds to fusion proteins allowingthe location of the fusion protein to be determined.

B)	The reaction is only dependent on the presence of GFP and oneother cofactor.

C)	It is easily cloned and expressed in bacterial cells.

D)	The presence of just a few molecules of GFP fusion proteins canbe sufficient for observing the proteins microscopically allowingthe study of its location and movements in the cell.

E)	It is derived from fire flies, which are easy to cultivate inthe lab.

You wish to determine the cellular location of a protein butunfortunately it is not particularly antigenic (can t develop astrong antibody response). How could you solve this problem?

A)	Create a fusion protein with an epitope tag that can bevisualized by incubation with fluorescently tagged antibody to theepitope.

B)	Create a fusion with green fluorescent protein (GFP).

C)	Express the protein as a fusion with biotin. The addition of GFPwill cause fluorescence.

D)	A and B might work.

E)	A, B, and C might work.

F)	None of the above will work.

A positive result for the yeast two-hybrid analysis means thefollowing:

A)	The proteins that you are studying can be made into fusionproteins, but do NOT interact with each other within the nucleus ofyeast.

B)	A fusion protein containing the Gal4p activation domain, hasbound to RNA polymerase resulting increase transcription ofnumerous genes, including the reporter gene, and formation ofcolonies.

C)	Two fusion proteins, one containing the Gal4p binding sitedomain and one containing the Gal4p activation domain, haveinteracted through their Gal4p domains resulting in transcriptionof the reporter gene.

D)	Two fusion proteins interact with each other and because of theGal4p binding site domain and the Gal4p activation domain containedin each fusion protein, the reporter genes are activated and thecells die resulting in no colonies.

E)	The colonies growing are expressing the two fusion proteins, butthe two proteins have not interacted with each other.

Which of the following is the approximate size of the humangenome?

3 Gm

300 Kb

3 Mb

3 Gb

3 Mm

Which of the following is correct about the structure orlocation of genes?

Question 22 options:

A)	Prokaryotic genes typically possess their own regulatorysequences that only control expression of a single gene.

B)	Eukaryotic genes often encode introns that are spliced outbefore translation.

C)	Eukaryotic genes are mostly located at the telomeres and thecentromeres of chromosomes.

D)	Eukaryotic genes are typically arranged in operons.

E)	Prokaryotic genes often encode exons that are spliced out beforetranslation

copperskunk824

EBIO 1210 Chapter Notes - Chapter 13: Genetic Engineering, Heterochromatin, Euchromatin

Document Summary

Get access

Related Documents

EBIO 1210 Study Guide - Final Guide: Dna Replication, Messenger Rna, Central Dogma Of Molecular Biology

EBIO 1210 Lecture Notes - Lecture 13: Chromosome, Euchromatin, Dna Ligase

EBIO 1210 Chapter Notes - Chapter 14: Cytosol, Nonsense Mutation, Signal Peptide

Related Questions