EE 2950 Chapter : Appendix C
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Because the capacitor voltage is zero at t = 0, the charge on the capacitor is zero at t = 0. Then using equation 3. 5 in the text, we have t. 20- resistance we obtain a resistance of 6. 667 , which is in series with the 5- resistance. Thus, the total resistance seen by the 15-v source is 5 + 6. 667 = 11. 667 . The source current is 15/11. 667 = 1. 286: the current divides between the 10- resistance and the 20- resistance. Using equation 2. 27, the current through the 10- resistance is. Finally, the power dissipated in the 10- resistance is. The equivalent capacitance of the two capacitors in series is given by. The input power to the motor is the output power divided by efficiency. However the input power is also given by. Iv rms rms cos( in which cos( is the power factor. Solving for the current, we have rms v rms.
