PHYS 2102 Chapter : 3

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azuremammoth471

15 Mar 2019

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21. 1 two equally charged particles are held 3. 2 10 3 m apart and then released from rest. The initial acceleration of the first particle is observed to be 7. 0m / s2 and that of the second to be. If the mass of the first particle is 6. 3. 10 7kg what are (a) the mass of the second particle and (b) the magnitude of the charge on each particle. The forces on each particle are the same, since the electric force depends on the product of the charges. The acceleration that each charge experiences, however, will be different, since the particles have different masses. Since the forces are equal, we can write m1a1 = m2a2 m2 = a1 a2 m1 = 9. 0m / s2 6. 3 10 7 kg = 4. 9 10 7 kg. We can calculate the magnitude of the force and use it to find q.

Related Questions

Two equally charged particles, held 4.8 x 10-3 m apart, arereleased from rest. The initial acceleration of the first particleis observed to be 6.1 m/s2 and that of the second to be 8.9 m/s2.If the mass of the first particle is 5.7 x 10-7 kg, what are (a)the mass of the second particle and (b) the magnitude of the charge(in C) of each particle?

Two particles, with identical positive charges and a separation of2.10 x 10^-2m, are released from rest. Immediately after therelease, particle 1 has an acceleration a1 whose magnitude is 4.60x 10^3 m/s (squared), while particle 2 has an acceleration a2 whosemagnitude is 8.50 x 10^3 m/s (squared). Particle 1 has a mass of5.90 x 10^-6kg.

(a) Find the charge on each particle.
___________C

(b)Find the mass of particle 2.
___________kg

Two particles of identical mass m and charge q aresuspended bymeans of uncharged threads of identical length L whosemasses arenegligible. Due to the forces present, each particle isin a stateof equilibrium. Due to the symmetry of theconfiguration, eachthread forms the angle (data) with the verticaldirection, asdepicted in the diagram. Standard gravity actsverticallydownward.