CHEM 14A Chapter Notes - Chapter M: Limiting Reagent, Combustion Analysis, Calcium Carbide

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What is the percentage yield of carbon dioxide: 2c8h18 (l) + 25o2 (g) 16co2 (g) + 18 h2o (l) 2mol c 8 h 18 x 44. 01 g. mol-1 = 2. 16 x 103 g yield = 2. 16 kg x 100% = 85. 2% b. c. d. = 5. 55 mol h2o: 1. 56 mol cac2 x. = 3. 12 mol h20 needed: since we have more than 3. 12 moles of water, water is the excess and calcium carbide is the limiting reactant. So calcium carbide determines how much ethyne can be produced: 1. 56 mol cac2 x. 1 mol ca c2 x 26. 04 g. mol-1 = 40. 6 g c2h2: excess in h2o, 5. 55g -3. 12g = 2. 43 g x 18. 02 g. mol-1 = 43. 8g. Combustion analysis: a combustion analysis was carried out on 162. 1 g of a new compound with only c, h, and o. The mass of water and carbon compound was 1. 902g and 3. 095g respectively. What is the empirical formula of the compound.

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