PHYSICS 135 Chapter Notes - Chapter 6: Implicit Function, Solar Energy Generating Systems, Rolling Resistance
Document Summary
W fs mgs (6. 75 kg) (9. 80 m/s )(4. 00 m) 265 j. In part (b), if the cable pulls horizontally. In part (a), when the cable pulls horizontally. In each case the forces are constant and the displacement is along a straight line, so. 0 = and when it pulls at 35. 0 above the horizontal. If the cable pulls on the car at 35. 0 above the. Set up: the bucket rises slowly, so the tension in the rope may be taken to be the bucket(cid:146)s weight. Execute: (b) gravity is directed opposite to the direction of the bucket(cid:146)s motion, so eq. (6. 2) gives the negative of the result of part (a), or 265 j (c) the total work done on the bucket is zero. Evaluate: when the force is in the direction of the displacement, the force does positive work. When the force is directed opposite to the displacement, the force does negative work.
