PHYSICS 135 Chapter Notes - Chapter 17: Phase Transition, Lake Superior, Jmol
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C5 (9/5)(56. 7) 32 134. 1 f (9/5)(31. 1) 32 88. 0 f. Evaluate: fahrenheit degrees are smaller than celsius degrees, so it takes more f(cid:176) than c(cid:176) to express the difference of a temperature from the ice point. Identify: convert each temperature from (cid:176)c to (cid:176)f. F (5/9)(107 32) 41. 7 c (5/9)( 18 32) Evaluate: the temperature increase is 21 c(cid:176), and this corresponds to (21 c ) Execute: a temperature increase of 10 k corresponds to an increase of 18 f(cid:176). Identify: convert t in kelvins to c(cid:176) and to f(cid:176). Evaluate: kelvin and celsius degrees are the same size. Fahrenheit degrees are smaller, so it takes more of them to express a given t value. T is the same on the celsius and kelvin scales. Evaluate: the magnitude of the temperature change is larger in f(cid:176) than in c(cid:176). 32 ) 273. 15 there is no temperature at which celsius and kelvin thermometers agree.
