MATH 1F92 Lecture 14: Math+1F92-+9.1-+Estimating+a+Population+Proportion+Part+2+Fill+In

• School: Brock University
• Department: Mathematics and Statistics
• Course: MATH 1F92
• Professor: dr.christina

Document Summary

From the previous lecture, we now have a way of estimating whereabouts the population proportion may lie. For a sample proportion to be normally distributed, 2 conditions have to be met: We would now instead of using (cid:370)p(cid:371) for the conditions, we would have. Replacing p with p^ to use ^ instead: ^(cid:4666)(cid:883) (cid:4667)(cid:3410)(cid:883)(cid:882) (cid:884)(cid:4667)(cid:3409)(cid:882). (cid:882)(cid:887) occur. Conditions for a confidence interval to for a population proportion by the following: So in the same sense, if we defined a (cid:4666)(cid:883) (cid:4667) (cid:883)(cid:882)(cid:882)% confidence interval. , +(cid:2870) ^(cid:4666)(cid:883) ^(cid:4667) confidence interval for p is given by the following quantities: Suppose that a simple random sample of size n is taken from a population. Constructing a (cid:4666)(cid:2778) (cid:4667)% (cid:2778)(cid:2777)(cid:2777)% confidence interval for a population or the data are the result of a randomized experiment. Note: the conditions have to be met for us to be able to take a confidence.