COMM 215 Lecture 5: Midterm Review Problems Solutions

• School: Concordia University
• Department: Commerce
• Course: COMM 215
• Professor: wissamnawfal

Document Summary

X = 2. 689 median = 2. 29 mode = 2. 95. Q1=(. 25)(30) = 7. 5= the 8th ordered value = 0. 94. Q3=(. 75)(30) = 22. 5= the 23rd ordered value = 3. 51. Iqr = q3 q1 = 3. 51 0. 94 = 2. 57. S = 2. 166: 1. 5 (iqr) = 1. 5 (2. 57) = 3. 855, Two outliers whose values are 7. 96 and 8. 81. (note that the whiskers end at 0. 26 and 6. 71) Q1 : (. 25)(12) = 3rd value q1 = (15+22)/2 = 18. 5, Q2 : (. 5)(12) = 6th value q2 = (25+30)/2 = 27. 5, Q3 : (. 75)(12) = 9th value q3 = (35+38)/2 = 36. 5, X = 27. 083, i = (. 4)(12) = . 48. 40th percentile = the 5th ordered value = 24. 3: 16 (. 3) = 4. 8 30th percentile = 5th value = 9. 16 (. 7) = 11. 2 70th percentile = 12th value = 20 i = . 25(16) = 4th q1 = (9+9)/2 = 9, i= . 75(16) = 12th q3 = (20+21)/2 = 20.