Suppose there is a little block attached to a cord passing overapulley through a hole in the
Suppose there is a little block attached to a cord passingovera pulley through a hole in the horizontal frictionlesssurface. Atfirst the little block is revolving with an initialangular speed of6rad/sec at a distance r from the center of thathole. So if thischord is pulled from below until the new radius isr/6, then whatwill be the new angular velocity?
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w=work andw(i)=initial work
r= radius
m=mass
Hints given: L= r*p- = r*m *v(1)
v- =w*r
L(i)=r(i)*m*w(i)*r(i)
Eventually masses will cancel out so leftwithr(i)^2*w(i)--> solve for w(i)
L(f)=r(f)*m*w(f)*r(f)
Likewise mass will cancel out left r(f)^2*w(f)
Then plug in the values into equation L(i)=L(f) (setthem equalto each other to cancel out masses that way)
Conservation of angular momentum L(i)=L(f)
=L(0) -->the angular momentum constant
Solve forW(f)