PHYS 102 Lecture Notes - Lecture 25: Real Image, Virtual Image
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Note: next week of class is the last week of lectures. There will be a capa due on friday, but no plq due on tuesday. There will be a final exam review session sometime in mid-april before the final exam. 2 = (1/7) / d0 - (1/d0) / d0. M = -di/do = -0. 075 / 1 = - 0. 075. It is a real image that is inverted. Real image because di is positive, inverted because all real images are inverted. And then because it is virtual, it will be upright. (negative 2. 5 because real image = -m) https://docs. google. com/document/d/1ugplkg4czzlb6eljtsmvoyius5v5afaemkrs7red3fu/edit. Two converging lenses each with focal length f=30cm are placed 20 cm apart. An object is placed 35cm in front of one lens. This will now act as a virtual image for the second lens (because it"s on the opposite side from where the real object is located) But because lenses are 0. 2m apart, distance between virtual object and lens 2 is.