MATLS 2B03 Lecture Notes - Lecture 1: Adiabatic Process, Titanium
29 Aug 2016
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Department
Course
Professor
Dealing with a cycle of an arbitrary shape and size
Let us move from adiabat 1 to adiabat 2 in the clockwise direction following the isotherm
. The heat received,
H
1
TTH
1
Q
, depends on temperature as well as the distance between the
adiabats. If, however, H
1
Q
is divided by , then
H
1
TH
1
H
1
Q
T
depends on the distance between the
adiabats only. Now inspect Figure 1.
Figure 1
An arbitrary cycle can always be covered with a mesh of isotherms and adiabats. Let us choose
such distances between the adiabats that
H
HH
3
12
HHH
123
Q
QQ
TTT
(1)
In (1), H
i
Q
is a positive heat received by the engine from the i-th hot reservoir with temperature
H
i
T
If (1) holds for an upper branch of the cycle (positive work is done by the system), then it should
be valid for the lower part of the cycle (positive work is done on the system):
C
CC
3
12
CCC
123
Q
QQ
TTT
(2)
Document Summary
Dealing with a cycle of an arbitrary shape and size. Let us move from adiabat 1 to adiabat 2 in the clockwise direction following the isotherm. 1q , depends on temperature as well as the distance between the. Now inspect figure 1. depends on the distance between the. An arbitrary cycle can always be covered with a mesh of isotherms and adiabats. Let us choose such distances between the adiabats that. H iq is a positive heat received by the engine from the i-th hot reservoir with temperature. If (1) holds for an upper branch of the cycle (positive work is done by the system), then it should be valid for the lower part of the cycle (positive work is done on the system): C iq is a positive heat received by the i-th cold reservoir with temperature it. In view of what we know about jumps from one adiabat to another isothermally, the following is true:
