PHYSICS 1E03 Lecture Notes - Lecture 1: Electric Light
5 May 2016
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Well, we know that charge = coulombs (number of charge) / s (time) The amount of charge that is discharged within that hour = 470160 c: d = 0. 849m. By finding the frequency of the rotation (rotations /second), we can find, the current in the wire which is the charge / time. Therefore, the current in the wire will be: p = 241. 00 ohms. Total resistance after being stretched is 1. 27^2 x: the length is increased by 1. 27 which results in the cross sectional area being decreased by. 1. 27x also: combine the two resistivity of the bars, which will result in, the first thing we must note is that free charge density is referred to as the variable n. Then solve for time by the usual distance-speed-time formula: voltage at the customer"s house: Where vloss is the voltage loss that was lost by the resistance of the wire as the current travels through it.
