PCS 211 Lecture Notes - Friction
Document Summary
Mass is proportional to the area of the object. A force that acts along a line passing through the origin produces a zero torque(where most forces meet) Fx = 0 , fy = 0 and torque = 0. There are 3 unknowns (t, r, : t force exerted by the cable, f force exerted by the wall at the pivot. Apply the 2 conditions of equilibrium to obtain 3 equations. Fx = r cos t cos = 0. Fy = r sin + t sin wp wb = 0. So the weight of the ladder acts through its geometric center (its center of gravity) mg cos min. There is static friction between the ladder and the ground (fs = sn). Sum in the x in this case is = 0 therefore, p = fs and. Sum in the y in this case is = 0 therefore, n = mg.
