PHYS 121 Lecture Notes - Lecture 2: Electric Field
13 May 2018
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May 10, 2018
8:52 PM
2. Electric Fields Page 1
Two charges are fixed in place on the x-axis as shown. The charge at x = 0 is negative and has magnitude
q = 2 μC (1 μC = 10-6 C). The charge at x = d, (d = +12 cm), is positive and has magnitude Q = 4 μC. Find a
point x = x0along the x-axis at which the electric field is zero.
1. Zero
May 11, 2018
9:26 AM
2. Electric Fields Page 2
Document Summary
8:52 pm: electric fields page 1, zero. Two charges are fixed in place on the x-axis as shown. The charge at x = 0 is negative and has magnitude (cid:395) = (cid:1006) (cid:645)c (cid:894)(cid:1005) (cid:645)c = (cid:1005)(cid:1004)-(cid:1010) c(cid:895). Two point charges (q1 = -(cid:1007)(cid:645)c a(cid:374)d (cid:395)2 = (cid:1010). (cid:1008) (cid:645)c(cid:895) a(cid:396)e fi(cid:454)ed alo(cid:374)g the (cid:454)-axis, separated by a distance d = 8. 4 cm. Point p is located at (x, y) = (d, d). A third point charge q3 = (cid:1006). (cid:1005) (cid:645)c is (cid:374)o(cid:449) positio(cid:374)ed alo(cid:374)g the (cid:455)-axis at a distance d = 8. 4 cm from q1 as shown. How would you change q1 (keeping q2 and q3 fixed) in order to make the electric field at point p equal to zero: electric fields page 3. How would you change q1 (keeping q2 and q3 fixed) in order to make the electric field at point p equal to zero: electric fields page 4, electric field from arc of charge.
