RSM270H1 Lecture 22: 270 Case 1 kimi
26 Sep 2017
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Number of trips per hour = 60/25=2. 4 number of trains sent: 60/15=4. However, the forth train is still on the road and not reached the destination. There are only 3 trains completed the journey. Total passengers per hour = 3 * 180=540. Requirement = 15 min per departure= 4 arrivals per hour. 1 round trip for train = 50 minutes. 1 train can make = 60/50= 1. 2 trips per hour. Our group choose the 1 min interval since the link train arrives every five minute. Arrival rate of passengers not from the link train from 10:30 to 11:30, 10/minute. Total passengers from link train: 180 10% arrival at terminal one: 180*10%=18, every 5 mins. Arrival rate of passengers not from the link train from 11:30 to 12:30, 5/min, 25 per 5 minutes. Therefore: minimum capacity that the waiting area should have equals to 248.
