Calculus 1000A/B Lecture Notes - Lecture 29: Inflection Point, Maxima And Minima, Inflection

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Calculus 1000A Lecture 29 Section 4.3 Increasing and Decreasing Functions Continued
Prof: N. Kiriushcheva
01/1012018
Recall: The Concavity Test
a) If    for all x’ in an interval then the graph is concave upward on the interval
b) If    for all ‘x in an interval then the graph is concave downward on the interval.
There is another element in concavity that can be a useful definition, which can contribute to our overall
analysis of functions:
The Second Derivative Test
Suppose that f’’ is continuous near ‘c’:
a) If   and   , then f has a local minimum at ‘c’
b) If   and   , then f has a local maximum at ‘c’
Example 1:   
Look at the first derivative: y’= 2x thus there is a critical point y’(0)= 0
Look at the second derivative: y’’= 2 since this number is positive, the function has a local minimum
at f(0)= 0
o We can note that the concavity is concave upward for the entirety of the function- 
Example 2:   
Look at the first derivative: y’= 3x2 thus there is a critical point y’(0)= 0
Look at the second derivative: y’’= 6x when     and when    
o Since the sign of the second derivative changes, we know that the concavity changes
o Therefore, the point (0, 0) is an inflection point
Example 3:
Looking at the graph above, we can determine that (0, 0) is a critical point, as f’(0) does not exist recall
that derivatives do not exist at sharp edges
This critical point is also an absolute minimum
Inflection Point:
A point ‘p’ on a curve y= f(x) is called an inflection point if a function is continuous there and the curve
changes from concave upward to concave downward, or from concave downward to concave upward.
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Document Summary

Calculus 1000a lecture 29 section 4. 3 increasing and decreasing functions continued. Recall: the concavity test: if >(cid:882) for all (cid:858)(cid:454)(cid:859) in an interval then the graph is concave upward on the interval, if (cid:882), then f has a local minimum at (cid:858)c(cid:859, if (cid:4666)(cid:4667)=(cid:882) and (cid:4666)(cid:4667)

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