BI111 Lecture Notes - Lecture 2: Allele Frequency, Genotype Frequency, New Zealand National Rugby Union Team

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9 Feb 2017
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Cards Example
f(b)=#b allele/#allele
=45+45+23/244
=113/244
=0.463
F(B)=#B allele/#allele
=54+54+23/244
=131/244
=0.537
F(B)+f(b)=1
# allele=2(45+23+54)
=2(122)
=244
f(bb)=pxp=p2
=(0.463)2
=0.214
f(BB)=qxq
=q2
=(0.537)2
=0.288
f(Bb)=pxq+qxp
=2pq
=2(0.462)(0.537)
=0.497
The Hardy-Weinberg Principle
Mathematical model that predicts genotype frequencies: used as a null/control
All models have assumptions
1. Random Mating
2. Large Population Size
3. No migration/emigration
4. No selection
1.Random Mating
Example: Since p+q=1
Alleles segregate idepedetly
Wednesday January
All black cat
ss
176(38.0%)
p:f(s)=176+176+217/2(463)
=559/926
=0.615
Half black, half white(no tail)
Ss-217(46.99%)
q:f(S)=217+70+70/2(463)
=357/926
=0.385
f(ss)=p2=0.6152
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