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BIOL 2040 Lecture Notes - Lecture 4: Prokaryote, Archaea, Consensus Sequence

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violetgoat734
24 Aug 2020
School
York University
Department
Biology
Course
BIOL 2040
Professor
Kyle Belozerov

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Document Summary

Jan 23 biol2040: non template : coding sequence ; upstream, template ; down stream. 2: how r we going to start transcription. Step1 : rna polymerase binds to a promoter. Transcription factor (help the regulation, rna polymerase ) is a protein that controls the rate of transcription of genetic information from dna to messenger rna, by binding to a specific dna sequence. , 2. Stabilizing for that core promotor: tata box? (part of core promotor at eukaryote and prokaryote, can act as a basal promoter element) The regulatory sequences include the promoter region together with enhancer elements. Every gene has a promoter, which is the binding site for the basal transcriptional apparatus - rna polymerase and its co-factors: core promoter? (on/off switch) Core promoter the minimal portion of the promoter required to properly initiate transcription: transcriptional activator/repressor? (they are control up and down) Transcription factors that are activators boost a gene"s transcription.

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Related Questions

Shown below is the coding DNA sequence for a protein-codinggene. Given this coding DNA, draw the DNA template strand, andwrite the polypeptide sequence.

Don

A. Please identify the mRNA and polypeptide sequence for the below DNA using the genetic codon table. (Note: the direction of mRNA is important! Keep in mind that the genetic codons are read from 5’ to 3’ direction on mRNA. Also, RNA bases are A, U, C, G instead of A, T, C, G)

3’ – GTT – TAC – CTT – CTC – TCC – TCA – GAC – ATC – GCA – 5’ (Template strand)

5’ – CAA – ATG – GAA –GAG – AGG – AGT –CTG – TAG – CGT – 3’ (Non-template/Coding strand)

B. Please identify the mutation type (silent, missense, nonsense, frameshift) on the following DNA sequence as compared to the original sequence from question A.

3’ – GTT – TAC – CTT – CTC – TTC – TCA – GAC – ATC – GCA – 5’ (Template strand) 5’ – CAA – ATG – GAA –GAG – AAG –AGT – CTG – TAG – CGT – 3’(Non-template/Coding strand)

C. Please identify the mutation type (silent, missense, nonsense, frameshift) on the following DNA sequence as compared to the original sequence from question A.

3’ – GTT – TAC – CTT – ATC – TCC – TCA – GAC – ATC – GCA – 5’ (Template strand)

5’ – CAA – ATG – GAA –TAG – AGG – AGT – CTG – TAG – CGT – 3’(Non-template/Coding strand)

An RNA has the following sequence:

5' AGUCGAUCAUCAGU 3'

What is the sequence of the NON-TEMPLATE/CODING strand of the DNA from which this RNA was transcribe?

5' ACTGATGATCGACT 3'

5' TGACUACUAGCUGA 3'

5' TCAGCTAGTAGTCA 3'

5' AGTCGATCATCAGT 3'

5' AGUCGAUCAUCAGU 3'