MGMT 1000 Lecture 13: MGMT 1000 Lecture 13 Notes
MGMT 1000 Lecture 13 Notes – Base 10 to another base and An Alternative Conversion
Method
Introduction
• Proceeding to the next digit, 625 goes into 2999 four times with a remainder of 499, 125
into 499 three times with a remainder of 124, 25 into 124 four times, and so on.
• We get a final result of 1434445 It would be useful for you to confirm the answer by
converting the result back to base 10.
• This method is particularly simple if you are converting from decimal to binary, since the
alue that orrespods to a partiular it either fits or it does’t .
• EXAMPLE
• Convert 319310 to binary.
• The weights in binary are 4096, 2048, 1024, 512, 256, 128, 64, 32, 16, 8, 4, 2, and 1.
• Proceeding as before, the largest bit value in this conversion is the 2048 weight.
• Subtracting 2048 from 3193 leaves 1145 yet to be converted
• Thus, there is also a 1 in the 1024 place.
• No the reaider is −=.
• This eas that there are ’s i the , , ad 8 plaes.
• Continuing, you should confirm that the final result is 1100011110012
• Note that, in general, as the base gets smaller, the representation of a value requires
more digits, and looks bigger.
An Alternative Conversion Method
• Although the preceding methods are easy to understand, they are computationally
difficult and prone to mistakes.
• We will consider methods that are usually simpler to compute but are less intuitive.
• It is helpful to understand the reasons that these methods work, since the reasoning
adds insight to the entire concept of number manipulation.
Base 10 to another base
find more resources at oneclass.com
find more resources at oneclass.com
