BIOL3040 Lecture Notes - Lecture 6: Nuclear Membrane, Endoplasmic Reticulum, Endomembrane System

57 views2 pages
Department
Course
Professor

Document Summary

Nuclear envelope would not break down because phosphorylation of lamins allows the nuclear envelope to break down. Phosphor-null mutation: when you change an amino acid that normally gets phosphorylated to an amino acid that cant be phosphorylated (s, t, y gets mutated to a) Because ran gap is high in the cytosol to convert ran gtp to ran gdp, if ran gap goes in the nucleus, it would convert gtp too early and it would not be able to continue the cycle. No change because it is normally in the nucleus. Ran gep would get broken down in the proteasome which would decrease levels of gtp in nucleus. Interiors of the endomembrane systems are kind of like extracellular. Membrane asymmetry: arises in the golgi, flippases and floppases create membrane asymmetry by moving the phospholipids from one side to another in order to separated different phospholipids.

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers
Class+
$8 USD/m
Billed $96 USD annually
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
30 Verified Answers

Related Documents