MATH-UA 120 Lecture Notes - Lecture 1: Bisection, Decimal Mark, Sexagesimal

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6 Aug 2016
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As shown in the diagram, the vertices of the triangle are labeled a, b, and c, the center of the circle is labeled o, and perpendicular ad is drawn. Ab and ac are each 50 and cb is 60. Adb is now a right triangle, so the pythagorean theorem is required to find ad. Given that cb is bisected by ad because the line equidistant from two points is the perpendicular bisector of the line segment they form. Knowing this, it is simple to deduce that db is 30. Pythagorean theorem, or just remember that 30 and 50 are multiples of 3 and 5 in a. 3,4,5 triangle, making the last side, ad, 40. The question wants the radius of the circle, or ao. Because radii of a circle are all equal, we can say that ao and bo are equal. Let"s call the length of the radius x. Since we know ad is 40, od, should be 40-x.

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