BIOL 23100 Lecture Notes - Lecture 21: Ribose, Chloroplast, Starch
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9 Nov 2016
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Given genes A, B, and C with phenotypes:
Gene A Phenotype: Triceratops leg curvature;
Gene B Phenotype: Farfeggnuggen wing vein;
Gene C Phenotype: Muppeteritus antennae.
And given the following table of phenotype counts (where "+" refersto wild-type phenotype):
ABC = 236
AB+ = 6
A+C = 26
A++ = 124
+BC = 121
+B+ = 32
++C = 4
+++ = 314
Which gene is in the middle?
A. There is no middle gene. A is linked to B, but not to C.
B. B
C. A
D. C
E. There is no middle gene. A is on a different chromosomes than Band
Based on my working below, the
ABC | 326 | 34.20776 |
AB+ | 26 | 2.728227 |
A+C | 124 | 13.01154 |
A++ | 6 | 0.629591 |
+ BC | 4 | 0.419727 |
"+B+" | 121 | 12.69675 |
"++C" | 32 | 3.357817 |
"+++" | 314 | 32.94858 |
953 | 100 |
Recombination frequency = 32 AC is 13
I am stuck here on how to find the middle gene. Since AC is 13,AB is 2.72 and BC is 0.41 which is where I am getting stuck.
Can some one help me understand how to solve this.