01:960:285 Lecture Notes - Lecture 11: Hypergeometric Distribution, Poisson Distribution

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01:960:285 - lecture 11 - chapter 4. 3 & 4. 4: the binomial distribution and other discrete. Let x = number of heads obtained in 10 trials n = number of trials = 10, p = probability of success (in this case, heads) = 0. 5 x = 0, 1, 2, , , 10. X~b(n = 10, p = 0. 5) q = probability of fail (tails) = 1 - p = 1 - 0. 5 = 0. 5. To calculate the probability of obtaining exactly two heads . To calculate the probability of obtaining two heads or less . P(x 2) = p(x = 0) + p(x = 1) + p(x = 2) To calculate the probability of obtaining less than two heads . P(x < 2) = p(x 1) = p(x = 0) + p(x = 1) = 0. 0010 + 0. 00 8 = 0. 0108. Different ways of expressing notation for the probability of x equaling k .

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