PHYS 101 Lecture Notes - Lecture 21: Free Body Diagram, Net Force

21 views2 pages
School
Department
Course
Professor

Document Summary

Chapter 4: why things move as they do. There is a force exerted by the table on the block. This for(cid:272)e, (cid:449)hi(cid:272)h is perpe(cid:374)di(cid:272)ular to (cid:894)or (cid:862)(cid:374)or(cid:373)al(cid:863) to(cid:895) the surfa(cid:272)e of the table, pushes up on the block. The magnitude of the normal force is equal to the weight. To visualize the normal force, imagine that the table top is covered with springs: When an object, say a book, rests on the table, it squeezes the springs causing the springs to push back against the book. When an object is not accelerating (i. e. , whenever the velocity is constant), the sum of the forces must be zero. We dra(cid:449) the (cid:862)free (cid:271)od(cid:455) diagra(cid:373)(cid:863) (cid:894)a. k. a. a for(cid:272)e diagra(cid:373)(cid:895): Sum of forces = (normal force) + (weight) = 0. The net force on the block is 0. 0 = fnet = m a => a = 0. We ha(cid:448)e see(cid:374) the first t(cid:449)o of ne(cid:449)to(cid:374)"s la(cid:449)s of (cid:373)otio(cid:374):

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers
Class+
$8 USD/m
Billed $96 USD annually
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
30 Verified Answers

Related textbook solutions

Related Documents

Related Questions