PHY 158 Lecture Notes - Lecture 13: Blauw-Wit Amsterdam

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0. 1 p = 1 - (cid:3118)(cid:3117) p = 1 - (cid:2869)(cid:2871)(cid:2868) = 0. 966. Based on the conservation of charge, i expect the sum of vblue and vwhite to be 0. According to the conservation of charge law, charge cannot escape a closed system. The initial amount of charge in the system should equal the final amount. The result of vblue + vwhite is zero which is exactly what i expected. When the net charge on the sphere is zero and it is being probed with the proof plane, between negative charges. As a result, the farther positions, =(cid:883)(cid:885)(cid:887) (cid:883)(cid:890)(cid:882) (in reference to = 90 and = 45 ), should have a high density of positive charges. This is because since sphere a is already negatively charged, the presence of sphere b (positively charged) will allow more negative charge to linger towards it.

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