STATS 250 Lecture 23: Testing About a Population Mean

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STATS 250 Lecture Notes - Lecture 22: Confidence Interval, Test Statistic, Null Hypothesis

STATS 250 Lecture 23: Testing About a Population Mean

STATS 250 Lecture Notes - Lecture 24: Confidence Interval, Standard Deviation, Type I And Type Ii Errors

Document Summary

Population mean: examples, using our t table to find a p-value for a one-sided test. 1. 761: using to find for a test are test. Values of t-test our t table a p-value two-sided. 0:= 64versus : 64with n = 30 observations and the observed testing statistic is t. = 1. 12. you p-value test? t(29) : classical music. Values of t-test statistic: a researcher wants to test if high school students complete a maze more quickly while listening to classical music. For the general high school population the time to complete the maze is assumed to follow a normal distribution with a mean of 40 seconds. A random sample of 100 high school students will be selected and timed while listening to classical music. = 39. 1 sec; s = 4; n = 100 > 25 => clt applies, Normal (5) study results: the sample mean time was 39. 1 seconds and the sample standard deviation for the times was 4 seconds.

Related Questions

1. A sample size of n=15 is a simple random sample selected from a normally distributed population. Using Table C, find the critical value t* corresponding to a 95% confidence level in the following scenarios:

a.............to construct a confidence interval

b..............one-sided hypothesis test

c..............two-sided hypothesis test

(1 point) A random sample of 130 observations is selected from a binomial population with unknown probability of success p. The computer value of is 0.64.

(1) Test : : p = 0.65 against : p > 0.65. Use α= 0.05.

test statistic z =

critical z score

The final conclusion is

⭕ A. We can reject the null hypothesis that p = 0.65 and accept that p is > 0.65.

⭕ B. There is not sufficient evidence to reject the null hypothesis that p = 0.65.

(2) Test : p = 0.5 against :p < 0.65. Use α = 0.01.

test statistic z =

critical z score

The final conclusion is

⭕ A. We can reject the null hypothesis that p = 0.5 and accept that p is < 0.5.

⭕ B. There is not sufficient evidence to reject the null hypothesis that p = 0.5.

(3) Test : p = 0.55 against : p ≠ 0.55. Use α = 0.01.

test statistic z =

positive critical z score

oliver202166

A sample of 36 observations is selected from a normal population. The sample mean is 12, and the population standard deviation is 3. Conduct the following test of hypothesis using the 0.01 significance level: H0: μ ≤ 10 H1: μ > 10

a. Is this a one- or two-tailed test?

b. What is the decision rule, Reject H0 when Z > 2.33 or when Z <= 2.33 ?

c. What is the value of the test statistic? (Round the final answer to 1 decimal place.)

d. What is your decision regarding H0? (Reject or Accept) ?

e. What is the p-value, one, zero, or close to zero ?

amberwalrus562

STATS 250 Lecture 23: Testing About a Population Mean

STATS 250 Lecture Notes - Lecture 22: Confidence Interval, Test Statistic, Null Hypothesis

STATS 250 Lecture 23: Testing About a Population Mean

STATS 250 Lecture Notes - Lecture 24: Confidence Interval, Standard Deviation, Type I And Type Ii Errors

Document Summary

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