A car is traveling at a rate of 18 feet per second when the brakesare applied. The position function for the car is given by s =รขยย2.25t2 + 18t, where s is measured in feet and t is measured inseconds. Create a table showing the position, velocity, andacceleration for each given value of t.
t 0 1 2 3 4 5
s(t) _____ 15.75 27 _____ ______ 33.75
v(t) _____ 13.50 9 4.50 ______ ______
a(t) -4.50 -4.50 -4.50 -4.50 -4.50 -4.50
What can you conclude?
A) It takes 4 seconds for the car to stop, at which time it hastraveled 4.5 ft.
B) It takes 3 seconds for the car to stop, at which time it hastraveled 33.75 ft.
C) It takes 4 seconds for the car to stop, at which time it hastraveled 36 ft.
D) It takes 4 seconds for the car to stop, at which time it hastraveled 2.25 ft.
E) It takes 5 seconds for the car to stop, at which time it hastraveled 33.75 ft.
F) It takes 4 seconds for the car to stop, at which time it hastraveled 18 ft.
What equation did you use for v(t)? that is where I got stuck.