PHL 406 Lecture Notes - Pacificism, Pacifism, Principle Of Double Effect

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liamiannarelli

17 Dec 2021

School

Ryerson University

Department

Philosophy

Course

PHL 406

Professor

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Document Summary

There are two world views on the use of violence. The world is an absolute jungle and when the exercise of coercive violence by rulers is just a manifestation of this. That it is both necessary and right to have people who can exercise violent power over others. And through this it makes the world much less of a jungle as long as it is not unjustly exercised. Society is essential for humans to reach they maximum potential. Society is impossible without coercive violence / power. Have to deal with external threats and internal threats e. g. , fighting wars or dealing with usurpers. Society is integral to the development of humans, therefore we need to make it less of a. "jungle, and doing that through violence is right ( if you are in the right) It is not wrong to strike first / engage in violence first.

Related Questions

Brief and detail

If relativism is true, can you ever judge something as being morally wrong? Consider some really horrible actions, genocide, murder, slavery, torture or add your own. If you feel a relativist could say that these things are actually wrong, what gives them this ability? If they can't, why not?

Agree or disagree

Similarly to what I said in the first discussion on what morality means to us, I think everyone has their own set of moral principles and obligations. So I do think that relativism is true, to a point however. I used Adolf Hitler and the Nazi empire as an example in the first discussion so I will use that here. Hitler knew in his brain that what he was doing was good for his nation and arguably the world. Now, as a modern day society we can agree that was wrong. For him, it was good. In his own mind, he is right. But it is relative to the person. Generally speaking we all have similar notions of what is right and what is wrong. Most people would say that going out of your way to help someone else is a morally good principle. Selflessness in society is seen a good thing by the vast majority of people. When I say that relativism is good to a point, I mean that there is a general basis in society that deems actions as good or bad. And since most of us would all agree that hitlers actions were bad, then we say that he had bad moral principles, even though to him, they were good. It’s a little confusing even for me to put into words. Basically, if you actions are generally viewed in society as good, then you have good moral principles even if they vary from person to person. No one will have the exact same moral standards, but generally they all are very similar in society. So relativism is true until the point where the majority of society would deem your actions and wrong. I hope this makes sense.

Agree or disagree

If relativism is true, I don't think judging something as morally wrong is possible. Because the definition of ethical relativism is the moral standard only being correctly relative to each person/society, this means that the moral standard is created by you and/or the society you identify with and therefore eliminate the existence of an absolute moral principle. Since the moral standard is different for every individual, we cannot say that someone is morally wrong. If relativism is applied, that is. If a relativist were to say that they could judge someone as morally wrong, then that would contradict the main component of being a relativist. That every moral argument of yours is correct, therefore everyone else's is also correct. Quite problematic but that is my understanding on the matter

ell25

In a circuit containing only resistors, the basic (though notnecessarily explicit) assumption is that the current reaches itssteady-state value instantly. This is not the case for a circuitcontaining inductors. Due to a fundamental property of an inductorto mitigate any "externally imposed" change in current, the currentin such a circuit changes gradually when a switch is closed oropened.
Consider a series circuit containing a resistor of resistance andan inductor of inductance connected to a source of emf andnegligible internal resistance. The wires (including the ones thatmake up the inductor) are also assumed to have negligibleresistance.
Let us start by analyzing the process that takes place after switchis closed (switch remains open). In our further analysis, lowercaseletters will denote the instantaneous values of various quantities,whereas capital letters will denote the maximum values of therespective quantities.
Note that at any time during the process, Kirchhoff's loop ruleholds and is, indeed, helpful:
.
Part A
Immediately after the switch is closed, what is the current in thecircuit?
Hint A.1
How to approach the problem
Hint not displayed
ANSWER:

zero
Answer not displayed
Part B
Immediately after the switch is closed, what is the voltage acrossthe resistor?
Hint B.1
Ohm's law
Hint not displayed
ANSWER:

zero
Answer not displayed
Part C
Immediately after the switch is closed, what is the voltage acrossthe inductor?
Hint C.1
A formula for voltage across an inductor
Hint not displayed
ANSWER:

zero
Answer not displayed
Part D
Shortly after the switch is closed, what is the direction of thecurrent in the circuit?
ANSWER:
clockwise
counterclockwise
There is no current because the inductor does not allow the currentto increase from its initial zero value.
Answer not displayed
Part E
Shortly after the switch is closed, what is the direction of theinduced EMF in the inductor?
ANSWER:
clockwise
counterclockwise
There is no induced EMF because the initial value of the current iszero.
Answer not displayed
Part F
Eventually, the process approaches a steady state. What is thecurrent in the circuit in the steady state?
ANSWER:

Answer not displayed
Part G
What is the voltage across the inductor in the steady state?
Hint G.1
Induced EMF and current
Hint not displayed
ANSWER:
zero

Answer not displayed
Part H
What is the voltage across the resistor in the steady state?
ANSWER:
zero

Answer not displayed
Part I
Now that we have a feel for the state of the circuit in its steadystate, let us obtain the expression for the current in the circuitas a function of time. Note that we can use the loop rule (goingaround counterclockwise):
.
Note as well that and . Using these equations, we can get, aftersome rearranging of the variables and making the subsitution,
.
Integrating both sides of this equation yields
.
Use this last expression to obtain an expression for . Rememberthat and that .
Express your answer in terms of , , and . You may or may not needall these variables. Use the notation exp(x) for .
ANSWER:
=
Answer not displayed
Part J
Just as in the case of R-C circuits, the steady state here is neveractually reached: The exponential functions approach their limitsasymptotically as . However, it usually does not take very long forthe value of to get very close to its presumed limiting value. Thenext several questions illustrate this point.
Note that the quantity has dimensions of time and is called thetime constant (you may recall similar terminology applied to R-Ccircuits). The time constant is often denoted by . Using , one canwrite the expression

as
.
Find the ratio of the current at time to the maximum current.
Express your answer numerically, using three significantfigures.
ANSWER:
=
Answer not displayed
Part K
Find the time it takes the current to reach 99.999% of its maximumvalue.
Express your answer numerically, in units of . Use threesignificant figures.
ANSWER:
=
Answer not displayed

Part L
Find the time it takes the current to reach 99.999% of its maximumvalue. Assume that ohms and millihenrys.
Express your answer in seconds, using three significantfigures.
ANSWER:
=
Answer not displayed
seconds
Part M
Find the time it takes the current to reach 99.999% of its maximumvalue. Assume that ohms and henrys.
Express your answer in seconds, using three significantfigures.
ANSWER:
=
Answer not displayed
seconds
Part N
What fraction of the maximum value will be reached by the currentone minute after the switch is closed? Again, assume that ohms andhenrys.
Use three significant figures in your answer.
ANSWER:
=
Answer not displayed
Now consider a different situation. After switch has been closedfor a long time, it is opened; simultaneously, switch is closed, asshown in the figure. This effectively removes the battery from thecircuit.
The questions below refer to the time immediately after switch isopened and switch is closed.
Part O
What is the direction of the current in the circuit?
ANSWER:
clockwise
counterclockwise
The current is zero because there is no EMF in the circuit.
Answer not displayed
Part P
What is happening to the magnitude of the current?
ANSWER:
The current is increasing.
The current is decreasing.
The current remains constant.
Answer not displayed
Part Q
What is the direction of the EMF in the inductor?
ANSWER:
clockwise
counterclockwise
The EMF is zero because the current is zero.
The EMF is zero because the current is constant.
Answer not displayed
Part R
Which end of the inductor has higher voltage (i.e., to which end ofthe inductor should the positive terminal of a voltmeter beconnected in order to yield a positive reading)?
Hint R.1
How to approach the problem
Hint not displayed
ANSWER:
left
right
The potentials of both ends are the same.
The answer depends on the magnitude of the time constant.
Answer not displayed
Part S
For this circuit, Kirchhoff's loop rule gives
.
Note that , since the current is decreasing. Use this equation toobtain an expression for .
Hint S.1
Initial and final conditions
Hint not displayed
Hint S.2
Let us cheat a bit
Hint not displayed
Express your answer in terms of , , and . Use exp(x) for .
ANSWER:
=
Answer not displayed

PHL 406 Lecture Notes - Pacificism, Pacifism, Principle Of Double Effect

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