Consider an infinite hollow pipe of radius R with anetpositive charge uniformly distributed on its outer surface.Let'sdefine our x axis to coincide with the pipe's central axis,asshown below. Symmetry in this situation requires that ifE(electric field) not equal to 0 in the pipe's emptyinterior, Emust point radially away from or toward the pipe'scentral axis, andcan depend at most on the distance r one is fromthat axis.
(a) imagine that E not equal to 0 inside the pipe'sinterior.Briefly explain why symmetry means that E at P cannotpoint in adirection like the Ep vector shown above.
(b) Use Gauss law to show that in fact E = 0 at allpointsinside the pipe's hollow interrior. (This is analogous to thepartof the shell theorem that says that E 0 inside a hollwspehricalshell.