When dealing with Hardy Weinberg Equations, why does the alliedfrequency always add up to 1 (p+q=1)?
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Consider a wildflower population with the following allele and genotype frequencies.
Frequency of the CRallele: p = 0.6
Frequency of the CWallele: q = 0.4
Frequency of CRCR: 50%
Frequency of CRCW: 20%
Frequency of CWCW: 30%
Is this population in Hardy-Weinberg equilibrium?
No, the frequency of genotype CRCWis too low. |
No, the frequency of genotype CRCRis too low. |
Yes, the genotype frequencies are what we would expect for a population in Hardy-Weinberg equilibrium. |
No, the frequency of genotype CWCWis too low. |
A population of butterflies has an allele B for big spots on the wings and b for small spots on the wings. The table below provides data about this population.
Regarding these data about the butterfly population, which of the following statements is correct? 1-The population is not in Hardy-Weinberg equilibrium because the genotype frequency of bb is greater than it would be in equilibrium. | ||||||||||||
2-The population is in Hardy-Weinberg equilibrium because the number of B alleles is equal to the number of b alleles. | ||||||||||||
3-The population is not in Hardy-Weinberg equilibrium because p 2 and 2pq are different. | ||||||||||||
4-The population is in Hardy-Weinberg equilibrium because half of the heterozygotes are B and half are b. |