🏷️ LIMITED TIME OFFER: GET 20% OFF GRADE+ YEARLY SUBSCRIPTION →
Log in
Biology
1
answer
0
watching
94
views

Sickle-cell anemia is caused by a mutation in the b-globin gene.Heterozygotes for the Hbs disease allele have someprotection from malaria relative to wild-type, but Hbshomozygotes rarely live to produce offspring. 50 individualshomozygous for the normal (non-disease) allele produced a total of47 children. 50 heterozygous individuals produced a total of 55children. 50 Hbs homozygous individuals produced a totalof 0 children. What is the average fitness per individualof the heterozygotes? What is the relative fitness of thehomozygous normal individuals?

Watch
1
answer
0
watching
94
views

For unlimited access to Homework Help, a Homework+ subscription is required.

Reid Wolff
Reid WolffLv2
28 Sep 2019

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
Share

Related textbook solutions

Molecular Cell Biology
8 Edition,
Lodish
ISBN: 9781464183393
Biology: Science for Life with Physiology
6 Edition,
Belk
ISBN: 9780134555430
Biology
2nd Edition, 2013
Openstax
ISBN: 9781947172517
Concepts of Biology
OER Edition,
Openstax
ISBN: 9781938168116
Essentials of Biology
5 Edition,
Mader
ISBN: 9781259660269

Related questions

Sickle cell anemia is caused by a recessive allele symbolized S; the normal hemoglobin allele is symbolized as A. The S allele is thought to be held at high frequencies in malarial regions because heterozygotes are resistant to malaria. In Nigeria, w for SS individuals is 0.14, w for AS individuals is 1, and w for AA individuals is 0.88. What are the expected gene frequencies?

(w=fitness or relative fitness)

The correct answer is . freq(A) = .88, freq (S) = .12, i just need the math.

Q49. Which of the following is NOT true?

If a genetic disease reduces fertility and the allele thatcauses the disease offers no other advantage, the allele willlikely eventually disappear, due to natural selection.

Natural selection does not favor individuals who are homozygousfor the sickle-cell allele, because these individuals typically diebefore they are old enough to reproduce.

Individuals who are heterozygous HbA/HbS areprotected from malaria, and this is why sickle-cell diseasepersists in wetter, mosquito-prone regions in Africa.

In regions where malaria does not occur, individuals who areheterozygous HbA/HbS have a fitness advantageover those who are homozygous for the normal hemoglobin allele(HbA).

Q50. AFTER malaria is cured, the frequency of the HbSallele should decrease in regions with lots of mosquitoesbecause:

People will no longer die from sickle-cell disease in theseregions.

Having one copy of the HbS allele will no longer beadvantageous in these regions.

Natural selection will no longer act on the HbS alleleat all in these regions.

All alleles associated with genetic diseases eventuallydisappear.

Q52. If the frequency ofthe HbS allele is 0.4 in a population, what is thefrequency of the HbAallele (assuming this is atwo-allele system)?

Q53. Which of the following would be sufficient for theHardy-Weinberg equation to accurately predict genotype frequenciesfrom allele frequencies?

p + q = 1

The population is not evolving due to natural selection.

The population is not evolving due to any of the conditions thatdisrupt Hardy-Weinberg equilibrium.

The population is infinitely large.

Q54. In a village, if the proportion of individuals who havesickle-cell disease is 0.25, and the population is assumed to be atHardy-Weinberg equilibrium, what is the expected frequency of theHbS allele? (Hint: What is the genotype of people withsickle-cell disease, and how is that genotype represented in theHardy-Weinberg equation?)

0.1250.250.50.75

Q55. In the same village, what proportion of the populationshould be heterozygous HbA/HbS, according to theHardy-Weinberg equation?

Use the following passage to answer the nextthree questions.

It has been hypothesized that people who are heterozygous forthe allele that causes the deadly genetic condition cystic fibrosis(which, among other symptoms, reduces fertility) are more resistantto the deadly disease tuberculosis.

Q56. If the cystic fibrosis allele protects against tuberculosisthe same way the sickle-cell allele protects against malaria, thenwhich of the following should be true of a comparison betweenregions with and without tuberculosis?

Cystic fibrosis deaths should be more common in regions withtuberculosis.

Cystic fibrosis deaths should be less common in regions withtuberculosis.

Cystic fibrosis deaths should be equally common in both types ofregions.

Regional differences in the cystic fibrosis death rate should bepurely random and unpredictable.

Q57. A person who is heterozygous for the cystic fibrosis allelemoves to a small, isolated community where no one previouslycarried the allele. If the cystic fibrosis allele protects againsttuberculosis the same way the sickle-cell allele protects againstmalaria, what should happen to the frequency of the cystic fibrosisallele in the community over time, and why?

The cystic fibrosis allele should disappear from the population,because a single individual with the allele is not enough for it toproliferate.

The cystic fibrosis allele should increase to a relatively highfrequency, because heterozygotes with the allele will be morelikely to survive than others.

The cystic fibrosis allele should become fixed in thepopulation, due to genetic drift.

The cystic fibrosis allele should either disappear or increasein frequency, depending on chance as well as on tuberculosisprevalence and death rate.

Use the following additional passage to answer the nextquestion.

Suppose you travel to the future, to a time when neithercystic fibrosis nor tuberculosis have caused any deaths for manygenerations. In all of these future populations, thecystic fibrosis allele still exists at a low frequency.

Q58. You visit a huge city with millions of people. If you wereto start sampling the cystic fibrosis allele from one generation tothe next, what should happen to its frequency over the next fewgenerations, and why?

The allele frequency should change a lot from one generation tothe next due to random genetic drift.

The allele frequency should not change much from one generationto the next because the population is large.

The allele frequency should steadily increase due to naturalselection.

The allele frequency should steadily decrease due to naturalselection.

Sickle-cell anemia is an interesting genetic disease. Normal homozygous individuals (SS) have normal blood cells that are easily infected with the malarial parasite. Thus, many of these individuals become very ill from the parasite and many die. Individuals homozygous for the sickle-cell trait (ss) have red blood cells that readily collapse when deoxygenated. Although malaria cannot grow in these red blood cells, individuals often die because of the genetic defect. However, individuals with the heterozygous condition (Ss) have some sickling of red blood cells, but generally not enough to cause mortality. In addition, malaria cannot survive well within these "partially defective" red blood cells. Thus, heterozygotes tend to survive better than either of the homozygous conditions. Assuming an African-American child were born each day of the year, statistically, one of these children per year would have a severe form of sickle-cell anemia (ss). Assuming Hardy-Weinberg equilibrium of these alleles, what is the percentage of the African-American population that are sickle-cell carriers? (Note that these carriers will turn out to be more resistant to malaria, should they decide to visit a malaria-infested part of the world; sometimes there are bizarre perks to being a carrier of a horrible disease!). Enter a percentage number (round up to whole number) without percent sign (%)

Weekly leaderboard

Home
Homework Help 3,900,000
Biology 460,000
Start filling in the gaps now
Log in