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Cystic Fibrosis is an autosomal recessive disease which usually leads to death in the early to mid-20s. Carriers are not affected. The normal allele is F and the disease allele is f. You want to know how strong selection is against the disease allele, and set out to find its selection coefficient (s).

What are the relative fitness of the normal genotypes? (0.5 pt. each, no calculation needed)

ωFF =

ωFf =

You find the following data regarding the number of people affected by CF 30 years ago, and today, from genetic tests of US hospital patients. In both years, the sample size was of 1348 individuals chosen at random from the population. It is known that that the mean relative fitness of the 1987 population was 0.919.

Distribution

FF

Ff

ff

1987

661

566

121

2018

782

489

77

find the relative fitness of the disease genotype, and the selection coefficient of the disease allele. Show your work and round results to 2 significant figures :

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Sixta Kovacek
Sixta KovacekLv2
28 Sep 2019

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