5. If 1/1000 individuals with your genetic background are carriers for a certain autosomal, recessive disease allele, what is the chance that both you and your spouse will be carriers?

6. (Related to 5) What is the chance that you will both be carriers and have an affected child?

7. (Related to 5 and 6) If you are a carrier for this disease allele and your spouseâs status is unknown, what is you chance of having a child with the disease?

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Sixta KovacekLv2

28 Sep 2019

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A.Phenylketonuria is a human disease caused by a recessive allele (p). Normal individuals have at least one dominant allele (P). If 2 cousins who are heterzygotes marry, perdict the percentage (%) of their children with each of the following genotypes or phenotypes:

1. Homozygous dominant

2. Carriers like their parents

3. Children with phenylketonuria

B. For any one child born to these parents, what is the chance that she/he will be totally normal?

Sandra and Steven are expecting their first child. Each have one female sibling who is affected with PKU (Phenylketonurea) and no other family history of the disorder is known on either side. They ask what their risk is of having an affected child. What do you tell them? A) They must both be heterozygotes so their risk of having an affected child is 25%.

B) There is a 50% chance they are heterozygous carriers so they should get genetic testing.

C) Since neither one of them is affected, they are not at risk of having an affected child.

D) You can't give them any firm answers because you don't know their genotypes.

E) Since this disorder is an autosomal recessive no one in the next generation will have the disease.

Two parents who are each known to be carriers of an autosomalrecessive allele have four children. None of the children has therecessive condition.

What is the probability that two or more of the children are thecarriers of the recessive allele?

(To calculate this type of probability, you must consider allpossible birth orders of carriers. For example, if a question askedwhat is the probability the one of two children is a carrier, thereare two possible orders: 1) first child is a carrier, second childis not a carrier 2) first child is not a carrier, second child is acarrier. Calculate the probability of each possible occurance andadd the probabilities together to get the overall chance that onechild is a carrier. )

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