In fruit flies, three mutations ebony body (e) vestigial wings (vg) and antennadepia(a) result in black body color, short wings and legs that grow where antennae should be. The wild type conditions for these traits are a tan body color (e+) long wings(vg+) and normal antennae(a+). A cross was performed between a tan bodied, short winged female fly with normal antennae and a male with a black body, long wings, and antennapedia. The F1 were all tan with long winds and normal antennae. An f1 female was crossed with a male that was ebony bodied, vestigial winged and had antennapeidia. The 3,000 offspring showed the following:
Tan, vestigial wings, antennapedia 956
Ebony, vestigial wings. antennapedia 157
Tan, vestigial wings, normal antennae 12
Ebony, vestigial wings, normal antennae 355
Tan, long wings, normal antennae 158
Ebony, long wings, normal antennae 1,000
Tan. long wings, antennapedia 352
Ebony, long wings, antennapedia 10
Use a chi squared test to determine if the genes are independently assorting, indicate the chi square value, degrees of freedom and critical value at P=.05. If they are not indepently , then map the genes. Draw the two chromosomes of the F1 female and include the distance between each gene.
In fruit flies, three mutations ebony body (e) vestigial wings (vg) and antennadepia(a) result in black body color, short wings and legs that grow where antennae should be. The wild type conditions for these traits are a tan body color (e+) long wings(vg+) and normal antennae(a+). A cross was performed between a tan bodied, short winged female fly with normal antennae and a male with a black body, long wings, and antennapedia. The F1 were all tan with long winds and normal antennae. An f1 female was crossed with a male that was ebony bodied, vestigial winged and had antennapeidia. The 3,000 offspring showed the following:
Tan, vestigial wings, antennapedia 956
Ebony, vestigial wings. antennapedia 157
Tan, vestigial wings, normal antennae 12
Ebony, vestigial wings, normal antennae 355
Tan, long wings, normal antennae 158
Ebony, long wings, normal antennae 1,000
Tan. long wings, antennapedia 352
Ebony, long wings, antennapedia 10
Use a chi squared test to determine if the genes are independently assorting, indicate the chi square value, degrees of freedom and critical value at P=.05. If they are not indepently , then map the genes. Draw the two chromosomes of the F1 female and include the distance between each gene.
