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20 Apr 2019

The following data was obtained for an enzyme called “studyase” with and without an inhibitor.

What are the Vmax and KM for both the uninhibited and inhibited reactions (no need to plot)?

I really need help determining how to get the Vmax and KM from only the data in the table, thank you.

[S] mM Vi mM/min (no inhibitor) Vi mM/min (inhibitor)
0.700 0.200 0.180
0.400 0.180 0.150
0.310 0.160 0.110
0.098 0.120 0.070
0.066 0.100 0.050
0.040 0.070 0.040

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Hubert Koch
Hubert KochLv2
23 Apr 2019

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