1
answer
0
watching
67
views
13 Nov 2019

A mass of 1 kg is attached to the end of a spring immersed in a fluid with damping constant

c = 2.

To stretch the spring 2 m beyond its equilibrium position, it takes a force of 10 N. External vibrations create a force represented by

F(t) = 17 sin(2t).

The spring is compressed in the negative x direction x(0) = −2 m from its equilibrium with zero initial velocity. Find the equation for the position of the mass at any time t.

x(t) =

For unlimited access to Homework Help, a Homework+ subscription is required.

Reid Wolff
Reid WolffLv2
21 Jul 2019

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in

Related textbook solutions

Related questions

Weekly leaderboard

Start filling in the gaps now
Log in