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How would you prepare 250 mL if a .20 M formate buffer with a pH of 4.0 using formic acid (HCH02) and sodium formate (NaCHO2)? formic acid pka= 3.8

Ans: 1.38 g formic acid + 1.36 g NaCHO2

How Would you prepare the buffer above using just sodium formate?

Ans: 3.4 g

How did they get these answers?!?! please explain...

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Hubert Koch
Hubert KochLv2
30 Sep 2019
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