Log in
Chemistry
1
answer
1
watching
1,005
views

BICINE is a compound that contains a tertiary amino group. You have 0.5 L of 0.05 M BICINE with its tertiary amine in the unprotonated form. How much 0.2 M HCl or 0.2 M NaOH must be added in order to create a BICINE buffer solution pH = 7.5. (pKa = 8.3)

Watch
1
answer
1
watching
1,005
views

For unlimited access to Homework Help, a Homework+ subscription is required.

Avatar image
Liked by dayekassandraprangel
Reid Wolff
Reid WolffLv2
28 Sep 2019

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
Share
discord banner image
Join us on Discord
Chemistry Study Group
Join now

Related textbook solutions

Basic Chemistry
5 Edition,
Timberlake
ISBN: 9780134138046
Principles of Chemistry Molecular Approach
4th Edition,
Tro
ISBN: 9780134112831
Chemistry: Structure and Properties
2nd Edition,
Tro
ISBN: 9780134293936
Principles of Chemistry Molecular Approach
3rd Edition, 2014
Tro
ISBN: 9780321971944
Chemistry: A Molecular Approach
3rd Edition,
Tro
ISBN: 9780321809247
Chemistry: A Molecular Approach
5th Edition,
Tro
ISBN: 9780134874371
Principles of Chemistry: A Molecular Approach
4th Edition,
Tro
ISBN: 9780134895741
Chemistry: The Central Science
14th Edition, 2017
Brown
ISBN: 9780134414232

Related questions

1. Given 1 L of 0.05 M sodium bicine (conjugate base of the buffer), how much 0.1 N HCl must be added to make a bicine solution of pH 7.5? What is the molarity of bicine in the final buffer? The pKa is 8.26.

2. You take 2.38 g of HEPES in the acid form and bring the volume up to 100 mL with water. We will call this solution A. You then add 3 mL of 1 M NaOH to make solution B. Finally you add 7 more mL of 1 M NaOH to make solution C. What are the pH values of the 3 solutions? (The molecular weight of HEPES is 238. 3 g/mol and the pKa is 7.55; HEPES is a weak acid commonly used for biological buffers.

If you mix equal volumes of 0.1 M HCl and 0.2 M TRIS (free amine form), is the resulting solution a buffer? Why or why not?

The answer is:

Yes, b/c it contains equal concentrations of TRIS in the acid and free amine forms. When the 2 solutions mix, the concentrations (in the absence of a reaction) are 0.05 M HCl and 0.1 M TRIS b/c of dilution. The HCl reacts with half of the TRIS present, giving 0.05 M TRIS (protonated form) and 0.05 M TRIS (free amine form).

BUT I don't understand the answer. Where did the diluted concentrations come from? And then why did it only react with half of the TRIS? Please help !!!


Weekly leaderboard

Home
Homework Help 3,900,000
Chemistry 830,000
Start filling in the gaps now
Log in